Question

How much momentum will a dub bell of mass 10 kg transfer to the floor if it falls from a height of 80cm? Take its downward accerlation to be 10 metre per second.​

Answer 1

Answer:

40 kg m/s

Explanation:

The momentum transferred will be equal to the momentum of the dum bell right before touching the ground.

h = 80 cm = 0.8 m

a = 10 m/s²

u = 0 m/s

v² = u² +2 ah

   = 0² + (2 x 0.8 x 10)

   = 0 + 16

v  = √16

v  = 4 m/s

m = 10 kg

P = m v

  = 10 x 4 kg m/s

  =40 kg m/s

Answer 2

Given:

• Initial velocity = 0 (as it transfer to the floor)
• Acceleration = 10 m/s
• Distance = 80 cm = 0.8 m
• Final velocity = ?

Need to find:

• Momentum of the dub Bell

$\huge{ \underline{ \mathbb{SOLUTION:-}}}$

Calculating final velocity-

$\large \implies{ {v}^{2} = {u}^{2} + 2as} \\ \large \implies{ {v}^{2} = {(0)}^{2} + 2 \times 10 \times 0.8} \\ \large \implies{ {v}^{2} = 16} \\ \large \implies{v = \sqrt{16}} \\ \large \implies{v = 4 {ms}^{ - 1}}$

Momentum = Mass × velocity

$\large \implies{10 \times 4} \\ \large \implies{ \bold{40 \: kg \:{ms}^{ - 1}}}$

$\large{ \boxed{ \purple{Momentum = 40 \: kg \:{ms}^{ - 1}}}}$