Question

how much momentum will a dubbell of mass 10kg transfer to the floor if it falls from a height of 80m take its downward acceleration to be 10 metre per second.​

Answer 1

Explanation:

$\huge\mathfrak\red{ANSWER}$

mass of bell is 10kg

height, s=80/100 m = 0.8 m

a = 10m/s

u = 0

Using : v^2 = u^2 + 2as

= 4m/s

Momentum= 10×4 kg = 40kgm/s

Answer 2

Answer:

yr ans ya to p=0 h ya formula p=mv lagye to 400kgm/sec aayega

Explanation:v=√2gh

p=mv

totl transfer mane to ye hi aayega ok