Question

how much momentum will an object of mass 10kg transfer to the floor if it falls from a height of 5 M (a=g=10m/s)​

Answer 1

Answer:

AnsweR :

Momentum is 100 kgm/s

ExplanatioN :

Mass (m) = 10 kg

Height (h) = 5 m

Initial velocity (u) = 0 m/s

Acceleration (a) = 10 m/s²

Use 3rd ex of motion :

\begin{gathered}\boxed{\sf{v^2 \: - \: u^2 \: = \: 2gh}} \\ \\ \longrightarrow \sf{v^2 \: - \: 0^2 \: = \: 2 \: \times \: 10 \: \times \: 5} \\ \\ \longrightarrow \sf{v^2 \: = \: 20 \: \times \: 5} \\ \\ \longrightarrow \sf{v^2 \: = \: 100} \\ \\ \longrightarrow \sf{v \: = \: \sqrt{100}} \\ \\ \longrightarrow \sf{v \: = \: 10} \\ \\ \underline{\underline{\sf{Velocity \: is \: 10 \: ms^{-1}}}}\end{gathered}

v

2

−u

2

=2gh

⟶v

2

−0

2

=2×10×5

⟶v

2

=20×5

⟶v

2

=100

⟶v=

100

⟶v=10

Velocityis10ms

−1

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