how much momentum will an object of mass 10kg transfer to the floor, if it falls from a height of 5m.
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hi friend here is your answer,
s=1/2gt^2
t^2=2s/g
t^2=10/10=1 s
and, v=gt=10 m/s
So, momentum =m×v=10×10=100 kg m ans
s=1/2gt^2
t^2=2s/g
t^2=10/10=1 s
and, v=gt=10 m/s
So, momentum =m×v=10×10=100 kg m ans
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