how much NaOH is required to prepare its 500cm3 of 0.4 M solution
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Answered by
0
Answer:
500 / 0.4 = 1250
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Answered by
15
Explanation:
The Answer is 8 grams of NaOH.
Some pre-requisite knowledge to solve the question are:
Molar mass of NaOH = 40u
Molarity = Mass of solute × 1000/(Molar mass of solute × Volume of solution in mL).
It is given that M=0.4 and V= 500mL.
By putting the values in formula we get:
0.4=Mass of NaOH ×1000/(40×500).
On solving it gives Mass of NaOH required as 8 grams.
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