How much of 6.0M HCI needed to prepare 100mL of 2.5M HCI
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Answer:
41. 66 ml of HCl is added to 58.4 ml of water
Explanation:
M1v1=m2v2
6*x=2.5*100
X=250/6
X=41.6 ml
41.6 ml of HCl is added into 58.4 ml of water
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