Chemistry, asked by DhyeyM2, 9 months ago

How much of NaOH is required
To neutralize 15oo ml of O.IN HCl.

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Answers

Answered by pavitra7261

1

Answer:

6 gm

Explanation:

weight of NaOH:N*E.W.*V/100

(put value)

.Weight of NaOh required =0.1*40*1500/1000

= 6 gm

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