How much of naoh is requiredto neutrilise 1500cm^3 of 0.1N hcl
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Given Acid: 0.1 Normal H Cl , volume 1500 cm^3.
Normality = Molarity as H Cl is monoprotic. So we have 0.1 moles of Hydrogen ions in 1 Litre
We will have 0.1 *1500 cm^3/1000cm^3
= 0.15 Moles of H+ ions in the solution.
Concentration of Na OH required = 0.15 moles (to get 0.15 moles of OH-).
Mass of Na OH needed = 40 gms/mole * 0.15 moles= 6 grams.
(40 = Molar mass of Na OH).
Normality = Molarity as H Cl is monoprotic. So we have 0.1 moles of Hydrogen ions in 1 Litre
We will have 0.1 *1500 cm^3/1000cm^3
= 0.15 Moles of H+ ions in the solution.
Concentration of Na OH required = 0.15 moles (to get 0.15 moles of OH-).
Mass of Na OH needed = 40 gms/mole * 0.15 moles= 6 grams.
(40 = Molar mass of Na OH).
kvnmurty:
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