Question

How much of positive and negative charge is their in a cup of water , assume that cup contains 250 g of water?​

Answer 1

Answer:

the number of charges present in a 250g cup =1.33×107 C

Explanation:

Given a cup of water

We need to find the charge present in that cup

Let us assume that the cup is of 250g or 250 mL

We know that the molecular mass of water is 18g/ mol

Each molecule of water contains 2+8=10 electrons and protons.

So let the number of molecules present in a cup of water = n

=6.022×1023×250/18 =8.36×1024

Therefore

Total number of electrons or protons present in a cup of water be N

=n×10=8.36×1025

Total negative or positive charge is given by

q=N e

=8.36×1025×1.6×10-19 C

=1.33×107 C

So the number of charges present in a 250g cup =1.33×107 C