Question

How much of water is required to prepare 180ml of 10% Sodium sulphate solution?​

Answer 1

20ml of water is required to prepare 180ml of 10% Sodium sulphate solution

Explanation:

To make a salt solution by weight percent,

We use the formula w/v = mass of  salt solution which we need.

Here it is given tht

180ml of 10% Sodium sulphate solution

To determine the amount required of water to prepare 180ml of 10% Sodium sulphate solution

⇒ let the mass of water =x ml

⇒ mass of the solute=x+180ml)

⇒ x ml solute in x+180ml) of the solution

⇒ 10% = x/x+180 × 180

⇒ 10x+1800=100x

⇒ 90x=1800

⇒ x=20ml

20ml of water is required to prepare 180ml of 10% Sodium sulphate solution

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Answer 2

Answer:

The water is required to prepare 180ml of 10% Sodium sulphate solution is 20 ml.

Explanation:

• A sodium sulphate is defined as a salt of sodium of sulfuric acid.
• It has a suphate which is called as anhydrous it is white solid crystal.
• It is called as mineral thenardite.
• Glauber's salt or mirabilis has a formula $10H_{2} O$.

Given that:

180ml of 10% Sodium sulphate solution?

To find:

Amount of water required =?

Solution:

By applying the formula to find the salt solution weight,

w/v = mass of  salt solution which is required

here, it is the 180ml of 10% Sodium sulphate solution

when we determine the amount required of water to prepare 180ml of 10% Sodium sulphate solution

The mass of water =x ml

mass of the solute=x+180ml

x ml solute in x+180ml of the solution

10% = x/x+180 × 180

10x+1800=100x

90x=1800

x=20ml

Therefore, the amount of water required to prepare the water is 20 ml solution.

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