How much of water should be added to 15g of salt to obtain 15% salt solution?
Answers
Answered by
809
The mass by mass percentage of a solution is given by the following relation
where mass of solution = mass of solute + mass of solution
Here, mass of the solute (i.e. salt) = 15 g and the required concentration of the solution is 15 %.
Let the mass of water be a grams.
So,
15 = [15 / (15 + a)] X 100
Solving for a, we get
a = (100 - 15)g = 85 g
where mass of solution = mass of solute + mass of solution
Here, mass of the solute (i.e. salt) = 15 g and the required concentration of the solution is 15 %.
Let the mass of water be a grams.
So,
15 = [15 / (15 + a)] X 100
Solving for a, we get
a = (100 - 15)g = 85 g
Answered by
218
Answer:
85 mL
Explanation:
Given :
Mass of solute = 15 g
Mass % = 15 g
We know :
Mass % = ( mass of solute / mass of solution ) × 100
We can write :
Mass of solution = mass of solute + mass of solvent
Let :
Mass of solvent = y gram :
= > 15 = ( 15 ) / ( 15 + y ) × 100
= > 1 = ( 1 ) / ( 15 + y ) × 100
= > 15 + y = 100
= > y = 85 g
We know :
Density = Mass / Volume
= > Volume = mass / density :
Density of water = 1 g / mL
= > Volume = 85 / 1 mL
= > Volume = 85 mL
Therefore , we get required answer.
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