Question

how much pure alcohol has to be added to400 ml of a solution containing 15% alcohol to change the concentration of alcohol in the mixture to 32%?​

Answer 1

volume of percentage

------------------------------- • 100 = percentage

total volume of liquid

V

--------- • 15

400

V= 60

60 + x

------------ • 100 = 32

400 + x

==> 60 +x = 0. 32(400 + x)

==> 60 + x = 128 + 0.32x

==> 0.68x = 68

==> x= 100 mL