how much pure alcohol must be added to 400 ml of a 15% solution to make its strength 32 %
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Answered by
10
400ml has 15% alcohol i.e 60ml . This means we have 340ml of water or the liquid with which alcohol is mixed
Let V be the volume of alcohol added to make the strength 32%
then V/340+V = 32/100. solving this we get V as 160ml
so we need to add 160 -60 = 100ml of alcohol
A-100ml
Let V be the volume of alcohol added to make the strength 32%
then V/340+V = 32/100. solving this we get V as 160ml
so we need to add 160 -60 = 100ml of alcohol
A-100ml
kranti2004:
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Answered by
13
400ml has 15% alcohol i.e 60ml .
This means we have 340ml of water
or the liquid with which alcohol is mixed.
Let V be the volume of alcohol added to make the strength 32%
then,
V/340+V = 32/100. solving this we get V as 160ml
so we need to add 160 -60 = 100ml of alcohol
= 100ml is the answer.
This means we have 340ml of water
or the liquid with which alcohol is mixed.
Let V be the volume of alcohol added to make the strength 32%
then,
V/340+V = 32/100. solving this we get V as 160ml
so we need to add 160 -60 = 100ml of alcohol
= 100ml is the answer.
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