Question

How much pure alcohol must be added to 400ml of a 15% solution to make its strength 32%​

Answer 1

Answer:

Step-by-step explanation:

Let the amt of alcohol added is x

(15%*400 + 100%*x)/(400+x) = 32%

0.15*400+x = 0.32*(400 +x)

60 + x = 128 + 0.32x

0.68x = 68

x = 100 ml

Answer 2

Answer:

100ml

Step-by-step explanation:

in 400ml alcohol % is 15= 60ml

remaining part =340ml

now when alcohol is increased by 32% the remaining part is 68%

so 68%=340ml

32%= x?

x=340×32/68

x=160ml

so now alcohol % = 160ml

the added alcohol =160-60=100ml

hope you understand

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