Question

How much pure water must be mixed with 10 liters of a 25% acid solution to reduce it to a 10% acid solution? 15 L 25 L 11 L

Answer 1

15 later

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Answer 2

Answer:

15 l is the answer

Step-by-step explanation:

We need to reduce 25% to 10%

Let the amount of acid in the mix be x/100

This gives a final acid content of x/100×25%

The target concentration is 10%

Set x/100×25%=10%

x=10%×100/25%

x=40

Thus,40/100 of the final blend is the acid

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Let the total volume of the blend be v

We have 10 litres of acid so

40/100v=10

v=10×100/40=100/4=25 litres all together

Thus the added water is 25-10=15 litres

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