How much repulsion is between two electrons placed 1cm away from each other? Given that mass of an electronis9;1kg
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How far should two electrons be placed to show that the force of repulsion is equal to the weight of the electron?
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well one knows the force of repulsion between two charges say q1 and q2 placed at a distance say r m.
the force is by coulomb’s law
F = k. (q1.q2 )/r^2
you want that this repulsive force should be equal to mass of electron
me.g
wt. of the electron = me.g = k. (q1.q2 )/r^2
so the distance r = SQRT { k. (q1.q2 )/ (me.g) }
here q1=q2= electronic charge = 1.6.10^-19 c
me= mass of electron= 9.1 .10^-31 kg
g= 10m/s^2 and
K = 1/(4pi epsilon_0) = 9.10^9
so approx. the r= 5.33 m
so electron is very light particle.
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