How much should be subracted from 6x² - 8y² +10xy to get -2x²-2y²+12xy+20
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Answer:
(8x²-6y²-2xy-20) should be subracted from
(8x²-6y²-2xy-20 ) should be subracted from (6x² - 8y² +10xy ) to get (-2x²-2y²+12xy+20)
Step-by-step explanation:
Let p should be subtracted from 6x²-8y²+10xy to
get -2x²-2y²+12xy+20.
6x²-8y²+10xy - p = -2x²-2y²+12xy+20
=> 6x²-8y²+10xy -( -2x²-2y²+12xy+20)= p
=> 6x²-8y²+10xy +2x²+2y²-12xy-20 = p
=> 6x²+2x²-8y²+2y²+10xy-12xy-20 = p
=> (6+2)x²+(-8+2)y²+(10-12)xy-20 = p
=> 8x²-6y²-2xy-20 = p
=> p = 8x²-6y²-2xy-20
Therefore.,
(8x²-6y²-2xy-20 ) should be subracted from
(6x² - 8y² +10xy ) to get (-2x²-2y²+12xy+20)
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Answer:
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