Question

How much should be subracted from 6x² - 8y² +10xy to get -2x²-2y²+12xy+20

Answer 1

Answer:

(8x²-6y²-2xy-20) should be subracted from

(8x²-6y²-2xy-20 ) should be subracted from (6x² - 8y² +10xy ) to get (-2x²-2y²+12xy+20)

Step-by-step explanation:

Let p should be subtracted from 6x²-8y²+10xy to

get -2x²-2y²+12xy+20.

6x²-8y²+10xy - p = -2x²-2y²+12xy+20

=> 6x²-8y²+10xy -( -2x²-2y²+12xy+20)= p

=> 6x²-8y²+10xy +2x²+2y²-12xy-20 = p

=> 6x²+2x²-8y²+2y²+10xy-12xy-20 = p

=> (6+2)x²+(-8+2)y²+(10-12)xy-20 = p

=> 8x²-6y²-2xy-20 = p

=> p = 8x²-6y²-2xy-20

Therefore.,

(8x²-6y²-2xy-20 ) should be subracted from

(6x² - 8y² +10xy ) to get (-2x²-2y²+12xy+20)

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Answer 2

Answer:

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