how much should the pressure be increased in order to decrease the volume of the gas by 5 degrees at a constant temperature
Answers
Answered by
6
hiii mate
hope this helps you
Ideal gas equation (PV=nRT),
as temperature remains constant we can apply Boyle’s Law,
the law can be usefully expressed as P₁V₁ = P₂V₂.
V₂ =0.95 V₁ (as V₂ is 5% less than V₁)
P₁×V₁ = P₂×V₂
P₁×V₁ = P₂ (0.95×V₁)
P₂ = P₁/ 0.95
P₂ = 1.052 P₁
%increase in pressure= P2-P1/P1*100
%increase in pressure=1.052P1-P1/P1*100
%increase in pressure = 5.2
hope this helps you
Ideal gas equation (PV=nRT),
as temperature remains constant we can apply Boyle’s Law,
the law can be usefully expressed as P₁V₁ = P₂V₂.
V₂ =0.95 V₁ (as V₂ is 5% less than V₁)
P₁×V₁ = P₂×V₂
P₁×V₁ = P₂ (0.95×V₁)
P₂ = P₁/ 0.95
P₂ = 1.052 P₁
%increase in pressure= P2-P1/P1*100
%increase in pressure=1.052P1-P1/P1*100
%increase in pressure = 5.2
Similar questions