Question

How much should the pressure on a litre of water be changed to compress it by 0.10%?

Bulk modulus of water = 2.2 × 10^9 Pa.

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Answer 1

Bulk modulus B = change in pressure/ volume strain

= ◇P/◇V/V

Given -◇V/V= 0.10% = 1.0 × 10^-3

Change in pressure. ◇P = -(◇V/V).B

= 1.0 × 10^-3 × 2.2 × 10^9

= 2.2× 10^6 Pa

Answer 2

Answer:

P = 2.2 x 10^6 NM^-2

Step-by-step explanation:

Volume of water = 1 L = V

V = —0.1%

( V = ( -0.1 / 100 ) x 1 = 0.001)

K = -P / ( V/V ) = 2.2 x 10^9 NM^-2

P = -K x ( V / V )

P = 2.2 x 10^9 x ( 0.001 / 1 )

P = 2.2 x 10^6 NM^-2

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