Question

How much silver can be obtained by heating 207 g of Ag2CO3?
a.192
b.172
c.201
d.162

Answer 1

Answer:

The 207 g of ag gives 4 moles of silver

Answer 2

The mass of silver obtained is 160.5 g, which is near to d.162 g.

Given,

Mass of Ag2CO3=207 g.

To find,

mass of silver obtained.

Solution:

Ag2CO3 «→» 2Ag + CO2 + 1/2O2

Moles of Ag2CO3=207/276 (number of moles=given mass/molar mass)

Moles of Ag2CO3=0.75

In the above reaction, 1 mole of Ag2CO3 gives 2 moles of Ag.

Thus, 0.75 moles of Ag2CO3 gives=(0.75x2) mole of Ag

=1.5 moles of Ag.

Molar mass of Ag=107 g.

Moles=given mass/molar mass.

Let the mass obtained of silver be x.

1.5=x/107

x=107x1.5

x=160.5 g.

The mass of silver obtained is 160.5 g.

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