Chemistry, asked by ƒaiŗƴ, 9 months ago

How much silver is need to prepare 1.08 grams of silver nitrate.


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Answers

Answered by surykantgaikwad2104
2

Answer:

From the table above, we can see that 1 Mole of Silver Nitrate weighs about 169.87 grams. You can then say that the Formula Weight of Silver Nitrate is 169.87 grams. Note: The terms: Formula Weight and Molecular Weight are the same thing.

Answered by dawoodbilal1234587
3

Answer:

169.87 gram silver is needed to prepare 1.08 gram of silver nitrate .

hope so it will help you

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