Question

the sum of the digits of a two digit number is 9 on reversing the digit the new number formed is less than the original number by 9 find the original number​

Answer 1

Answer:

the original number is 54

Answer 2

Answer:

Step-by-step explanation:

Let the digit at one's place=x

Let the digit at ten's place=y

A to Q

x+y=9

x=9-y..........(1)

Reversing number=10x+y

10x+y=x+10y-9

10x-x+y-10y=-9

9x-9y=-9

x-y=-1

Putting value of x from eq1

9-y-y=-1

9-2y=-1

-2y=-1-9

y=-10/-2

y=5

Putting y in eq 1

x=9-5=4

Original number=x+10y

=4+10(5)

=4+50

= 54