Question

how much sodium acetate should be added to prepare a buffer solution of Ph = 4 in 1L of 0.1 mol acetic acid , if Ka = 1.8 * 10^-5​

Answer 1

Answer:

Applying Henderson's equation

pH=log

[Acid]

[Salt]

−logK

a

4=log[Salt]−log(0.1)−log1.8×10

−5

so, log[Salt]=2.2552

[Salt]=0.018g molL

−1

The molecular mass of CH

3

COONa=82

Amount of salt 0.018×82=1.476g

Step-by-step explanation:

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