How much steam at 100°C, will just melt down 3200 g of ice at - 10C?
Given : Specific heat capacity of ice = 2100 x J kg C
Specific heat capacity of water = 4200 J kg- c
Specific latent heat of steam - 2260 x 10^3 J kg
Specific latent heat of ice 336x 10^3 J Kg-1
please solve this question
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Let mass of steam be m
m×540=3200×0.5{0-(-10)} +3200×80
540×m= 16000+256000
m=503.7g
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