How much sulphuric acid required to prepare 0.1 molar sulphuri acid solution
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Stock = 98% ; D = 1.84 g/mL
0.1 M = 0.1 MOL/L
0.1 mol = 9.8 g
%C = m/DV
V = 9.8 /0.98 x 1.84
V = 5.43 mL
Take 5.43 mL from the stock and dilute it till 1 L
0.1 M = 0.1 MOL/L
0.1 mol = 9.8 g
%C = m/DV
V = 9.8 /0.98 x 1.84
V = 5.43 mL
Take 5.43 mL from the stock and dilute it till 1 L
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