How much time will light take to cross 2mm thick glass pane if refractive index of glasses is 3/2?
Answers
Answered by
275
Given conditions ⇒
Refractive Index = 3/2
∵ Refractive Index = Speed of the light in air/Speed of the light in glass.
3/2 = 3 × 10⁸/Speed of the light in glass.
∴ Speed of the light in glass = 2 × 10⁸ m/s.
Thickness of the glass plane = 2 mm.
= 0.2 cm.
= 0.002 m.
= 2 × 10⁻³ m.
∴ Time = (2 × 10⁻³)/(3 × 10⁸)
= 0.67 × 10⁻¹¹ s.
= 6.67 × 10⁻¹¹ s.
Hence, the time taken by the light is 6.67 × 10⁻¹¹ s.
Hope it helps.
Refractive Index = 3/2
∵ Refractive Index = Speed of the light in air/Speed of the light in glass.
3/2 = 3 × 10⁸/Speed of the light in glass.
∴ Speed of the light in glass = 2 × 10⁸ m/s.
Thickness of the glass plane = 2 mm.
= 0.2 cm.
= 0.002 m.
= 2 × 10⁻³ m.
∴ Time = (2 × 10⁻³)/(3 × 10⁸)
= 0.67 × 10⁻¹¹ s.
= 6.67 × 10⁻¹¹ s.
Hence, the time taken by the light is 6.67 × 10⁻¹¹ s.
Hope it helps.
Answered by
47
Answer:10^-11 seconds
Explanation:
Refractive index= speed of light in air÷ speed of light in glass
=> 3/2 = speed of light in air÷ speed of light in glass.
Now speed of light in air is 3*10⁸
Therefore speed of light in glass is 2*10⁸
( As '3' gets cancelled)
Now thickness= distance to be travelled
= 2mm= 2*10^-3 m
Time = Distance÷ Speed
=> 2*10^-3 ÷ 2*10^8
=> 10^-3-8
=> 10^-11 seconds
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