Question

how much tin is required to make an open box with length 80 cm breadth 25 cm and height 50 cm

Answer 1

2(lb+bh+lh)=TSA OF CUBOID
GIVEN:-
L=80
B=25
H=50
NOTE: ALL ABOVE DATA ARE IN cm
TO FIND : TSA - LB(TH AREA OF UPPER SIDE OF CUBOID)
TO FIND THE QUANTITY OF TIN REQUIRED TO MAKE AN OPEN BOX OF GIVEN DIMENSIONS
SOLUTION:-
TSA={2(80*25+25*50+80*50)-80*25}cm sq.
       ={2(2000+1250+4000)-2000}cm sq.
       ={2(7250)-2000}cm sq.
       ={14500-2000}cm sq
       ={12500}cm sq
THE REQUIRED TIN FOR MAKING BOX OF GIVEN DIMENSIONS IS 12500 cm sq

Answer 2

12500 sq. cm. of tin

Step-by-step explanation:

Tin box is a cuboid in shape with length 80cm, breadth 25cm, and height 50cm. The box is open, so the top surface of the cuboid is open.

To know how much tin is required for this box, we need to find the total surface area of the cuboid minus the open surface.

Total surface area of cuboid = 2 (lb + bh + lh) = 2 (2000 + 1250 + 4000) = 14500 sq. cm.

Open surface area = lb (as it is square) = 80 * 25 = 2000 sq. cm.

Tin surface area = 14500 - 2000 = 12500 sq. cm.

So the total tin required to make the box = 12,500 sq.cm.