how much volume of 0.2 N KClO3 will be prepared by adding 0.5 g of KClO3
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Decomposition of KClO
3
takes place as:
2KClO
3
(s)→2KCl(s)+3O
2
(g)
2 mole of KClO
3
=3 mole of O
2
∵ 3 mole O
2
formed by 2 mole KClO
3
∴2.4 mole of O
2
will be formed by:
(
3
2
×2.4) mol KClO
3
= 1.6 mole of KClO3
.
Mass of KClO3
= Number of moles × Molar mass
=1.6×122.5=196g
3
takes place as:
2KClO
3
(s)→2KCl(s)+3O
2
(g)
2 mole of KClO
3
=3 mole of O
2
∵ 3 mole O
2
formed by 2 mole KClO
3
∴2.4 mole of O
2
will be formed by:
(
3
2
×2.4) mol KClO
3
= 1.6 mole of KClO3
.
Mass of KClO3
= Number of moles × Molar mass
=1.6×122.5=196g
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