How much volume of chlorine is required to form 11.2 L of HCl at 273 K and 1 atm pressure ?
The balanced equation for the formation of HCl is
H2(g) + Cl2(g) → 2 HCl (g)
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Hence, calculate the number of moles as follows. Therefore, according to the reaction equation 2 moles of HCl is formed by 1 mole of chlorine. Hence, volume of chlorine formed by 0.499 mol will be as follows. Therefore, volume of chlorine will be 0.0111 liter.
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