How much volume of CO2 is produced on NTP on reaction between 0.25g CaCO3 with excess dilute HCL? CaCO3+HCL— CaCl2+CO2+H2O
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Answer: 56ml
as we know by the equation 1 mole of caco3 will produce mole of co2
So moles of caco3- 0.25/100
Moles of co2- 0.25/100
Volume is 0.25/100×22.4
Volume of 1 mole at ntp is 22.4
Explanation:
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