Question

How much volume of oxygen at stp in litres is required to burn 4g of methane gas completely?

Answer 1

Explanation:

CH4 + 2O2 gives CO2 + 2H20

16g of CH4 reacts with 64g of O2

4g of CH4 reacts with x of O2

Crossmultiplying

x= 64*4/16

x= 16g

no. of moles=16/32 = 0.5

volume = n * voluma at STP

volume = 0.5*22.4

11.2L