how much volume of water must be added to the 150 ml solution of 0.8 M so that its molarity becomes 0.4
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Answer: 300 mL of water is to be added
Explanation:
M1V1 = M2V2
=> 0.8 x 150 = 0.4 x V2
=> V2 = 0.8 x 150 / 0.4
= 2 x 150
= 300 mL
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