how much volume will 64g of oxygen gas occupy at 0 degree C temperature and one bar pressure. Explane pls
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Answer:
Oxygen exists as a diatomic molecular gas - O2
Molar mass O2 = 16*2 = 32 g/mol
64g O2 = 64 g / 32 g/mol = 2 mol O2 gas
At STP , 1 mol gas has volume = 22.4L or 22.4dm³
Volume of 2 mol gas at STP = 22.4*2 = 44.8L or 44.8dm³
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