Question

how much weight of KCLO3 is required to undergo thermal decomposition to yield 1.92 grams of O2. atomic mass of K, CL, O are 39, 35.5, 16 respectively.

Answer 1

"No of moles = Given mass / Molar mass

The molar mass Of KClO3 = 39x1+35.5x1+16x3

= 39+35.5+48

=122.5

Also, No of moles = given volume / 22.4

So, Given mass / Molar mass = Given volume / 22.4

       Given mass / 122.5 = 1.92 / 22.4

 

              Given mass= 1.92*122.5/22.4

               Mass required = 10.5 g"

Answer 2

$\huge \tt 10 \: \: g$