How much will be the coefficient of friction for moving a body of mass 80 kg by a force of 40 kg on a horizontal surface?
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Explanation:
Let a be the acceleration of the box.
The equation of motion of the box, ma=F−f (as friction force always opposite to applied force)
or 40a=80−60
or a=20/40=0.5m/s
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Given,
Mass of the body=80kg
On horizontal surface force applied by=40kg
To Find,
Coefficient of friction.
Solution,
Let a be the acceleration of the body
The equation of motion of the body,
ma=F−f (As we know friction force always opposite to applied force)
⇒40a=80−60
⇒a=20/40=0.5m/s
Hence, coefficient of friction will be 0.5.
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