Question

How much will be the resistance of another copper wire of same length but half the diameter

Answer 1

Answer:

As we know that resistance of a wire is inversely proportional to the square of its diameter

Explanation:

so if diameter is x

resistance =x²

so new diameter = x/2

new resistance = x²/4

ratio =x²/(x²/4)

4x²/x² = 4 times

so resistance would be 4 times

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Answer 2

Answer:

hi

Explanation:

Given,

diameter of copper wire = 0.5mm = 5 × 10-⁴ m

resistivity = 1.6 × 10^-8 ohm.m

resistance = 10 ohm

Length = ?

we know,

R = dL/A

where R , d , L and A are resistance , resistivity , length and cross section area.

10 = 1.6 × 10^-8 × L/(πr²)

L = 10 × 3.14 × (2.5 × 10^-4)² × 10^8/1.6

L = 10× 3.14 × 6.25/1.6=122.656

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