Question

How much work does the force F(x)=(−2.0/x) N do on a particle as it moves from x = 2.0 m to x =
5.0 m?

Answer 1

Explanation:

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Answer 2

Answer:

The work done by force on a particle is -0.79J.

Explanation:

Given:

$F=-\frac{2}{x} N$

$a= 5m$

$b=2m$

Here,

The force is denoted by F.

The upper limit is denoted by a.

The lower limit is denoted by b.

The work is denoted by W.

Now,

By the equation,

$W=\int\limits^a_b {\frac{-2}{x} } \, dx \\W=\int\limits^5_2 {\frac{-2}{x} } \, dx$

W = -0.79J

So, the work done by force on a particle is -0.79J.