Question

How much work done in moving a charge of 2 columbine from a point at 118 volt to a pint at 128 volts

Answer 1

Hi friend,

We know that,

Work done(W)=Vq

Here change in volt,

W= (V2-V1)q

W= (128-118)2

W= 20J.

Hope this helped you a little!!!

Answer 2

$\maltese \: \red{\mid{\underline{\overline{\textbf{Answer}}}\mid}}$

Work is said to be done when a force is applied on an object and the object undergoes displacement. It is measured in Joules.

In field of electricity work done is the, product of Potential difference between points and Charge which is moved. It is represented by :-

$\maltese \: w = vq$

In this equation :-

• w = work done
• v = potential difference
• q = Charge moved

Now , In this case, potential difference = 128 - 118V = 10V.

Charge moved = 2 Columb

Work done = ?

After inputting the known values in equation we get :-

$\maltese \: w = 10 \times 2$

$\maltese \: w = 20j$

Therefore the work done in moving charge = 20J.

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BY SCIVIBHANSHU

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