Question

how much work is done in lifting a 10kg box 1.5m of the floor?​

Answer 1

Answer:

Explanation:

Work done = Force × Displacement × Cosθ

F = mg => 10 × 10 = 100

D = 1.5m

θ = 180 => cos180° = -1

Work done = 100 × 1.5 × (-1)

= -( 150j)

Answer 2

Answer:

147 joules

Explanation:

w=mgh

= 10kg × 9.8m/s² × 1.5m

= 10kg × 14.7m²/s²

=147m²/s²

= 147 joules