Question

How much work is done in moving a charge of 2 C from a point of 118 V to a point of 128 V?

Answer 1

Answer:

Here we have,

Charge = 2C

Pd = 128 - 118 = 10V

As We know,

V = J/C

(V = volts, J = work done, C = charge)

=> 10 = J/2

=> J = 10 × 2 = 20J

Answer 2

Answer:

Answer:

Here we have,

Charge = 2C

Pd = 128 - 118 = 10V

As We know,

V = J/C

(V = volts, J = work done, C = charge)

=> 10 = J/2

=> J = 10 × 2 = 20J

Explanation: