how much work is done in moving a charge of 2 columns across two points having a potential difference 42 volt
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Answered by
13
#Hey mate here is your answer
We know that
V= WQ
42=W×2
W=42/2
W=21
hope it helps
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HemangaGogoi:
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Answered by
3
We have to take potential difference as work done per unit charge to bring it from a 0 to 12 volt.
Potential difference, volt=12 volt
Charge =2 columns
Volt =W/Q
12=W/Q
W=24J
Hence, the work done in moving a charge of 2 column across the two points having a potential difference is 12 volt is 24J.
Thanks
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