Question

how much work is done in moving a charge of 2C from a point 118 volts to a point at 128 volts

Answer 1

|∆W|=∆V×Q

Here,

|∆V| = 128-118 V= 10V

Q= 2 C

|W| = 10×2 = 20 V C or 20 J.

Answer 2

Heya user, here's your answer. :D

As we know, Potential Difference = Work Done/Quantity of Charge moved

And here, potential difference is 128-118 = 10V
Substituting the values, we get

$10 = \frac{WD}{2}$
WD = 10*2
WD = 20 Joules.


Hope it helped.
Regards