Question

how much work is done to displace horizontally a body by 30metre by a force of 250 Newton whose angle with the horizontal surface is 30 degree​

Answer 1

Given :

Displacement = 30m

Force = 250N

Angle between F and d = 30°

To Find :

Work done by the applied force.

Solution :

❖ Work done is defined as the product of force and displacement$.$

Mathematically, W = F • d

» W denotes work done

» F denotes force

» d denotes displacement

• It is a scalar quantity having only magnitude.
• SI unit : J
• CGS unit : erg

By substituting the given values;

➙ W = F • d

➙ W = F d cos ∅

Where ∅ denotes angle between F and d.

➙ W = 250 × 30 × cos 30°

➙ W = 7500 × √3/2

➙ W = 6487.5 J

Answer 2

$\huge{\underline{\underline {\mathtt{\purple{Hlw}\pink{Mate}}}}}$

$\Large\bold\blue{Given:}$

Displacement = 30m

Force = 250N

Angle between F and d = 30°

$\Large\bold\blue{To\:Find:}$

Work done

$\Large\bold\blue{Solution :}$

Work done = force × displacement or W = F • d

Let,

W = work done

F = force

d = displacement

Substituting the given values;

➙ W = F • d

➙ W = F d cos ∅

Where ∅ = angle between F and d.

➙ W = 250 × 30 × cos 30°

➙ W = 7500 × √3/2

➙ W = 6487.5 J

$\Large\fbox\red{Mark\: As\:Brainliest}$