Question

how much work is done when a package of 9 electron passing through 18 v battery

Answer 1

$\huge\mathbb{A~N~S~W~E~R}$

$<b>$

We know ,

Potential difference = work done/ charge

And,

Charge = +- ne

where n is integor and e is number of electrons.

Charge = 9*1.6 * 10^- 19 Coloumb's

Work done = 18 * 9 * 1.6 * 10^-19

$= 162 \times 1.6 \times {10}^{ - 19} \: joules$

mark as brainliest answer and plz follow me.

$<marquee>$

◌⑅⃝●♡⋆♡ THANK YOU ♡⋆♡●⑅◌