Question

how much work is required to form a bubble of 2cm radius from soap solution having surface tention 0.07N/m​

Answer 1

Answer:

$7.04 \times {10}^{ - 4} joules$

Explanation:

as we know the formula to calculate the work done in forming a drop is : Surface tension x change in surface area (or simply surface area)

soor a bubble it has two surface area (one on the inside and one on the outside)

W = T. 2xSA

= T*2*4πR^2

= 0.07*2*4*3.14*0.02*0.02

= 7.04×10^-4 J

Answer 2

Solution - Refer attachment