Question

How much work should be done on a bicycle of mass 20 kg to increage its speed from 2 m/s to 5 m/s

Answer 1

Let W be a work done to increase the speed of bicycle.
given,
mass m=20kg
initial velocity u=2m/s
final velocity V=5m/s
work done =Force (F) x Displacement
W=FxS. but F=ma
W=ma x S [a=acceleration of the bicycle ]
using V^2=U^2+2aS
2aS=5^2-2^2
aS =25-4/2
aS =21/2
aS =10.5m^2/sec.square
therefore,
W=m x (aS)
W=20x10.5
W=210 joules

Answer 2

Solutions:

We know that whenever work is done, an equal amount of energy is used up. So, the work done in this case will be equal to the change in kinetic energy of bicycle when its speed changes from 2 m/s to 5 m/s.

(a) In the first case;

Mass of bicycle, m = 20 kg

And, speed of bicycle, v = 2 m/s

So, kinetic energy, Ek = 1/2mv^2

=> 1/2 × 20 × (2)^2

=> 10 × 4

=> 40 J

(b) In the second case;

Mass of bicycle, m = 20 kg

And, speed of bicycle, v = 5 m/s

So, kinetic energy, Ek = 1/2mv^2

=> 1/2 × 20 × (5)^2

=> 10 × 25

=> 250 J

Now, Work done = Change in kinetic energy.

=> 250 - 40

=> 210 J

Thus, the work done is 210 J.