Physics, asked by jayanthramkpa5wgu, 1 year ago

How much work should be done on a motor bike of mass 90kg to increase its speed from 30m/s to 50 m/s (Ignore air resistance and friction).

Answers

Answered by anonymous64
1
\sf{\huge{Heya \: mate.\: Solution \\ below}}
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<font color = "red"><b><u>Answer - ↓</u></b></font color>



\sf{Work \: done \: =\: Energy\: = \: Kinetic\: Energy}



♠ Here,

mass (m) = 90 kg

initial velocity (u) = 30 m/s

final velocity (v) = 50 m/s




♠ So, Kinetic Energy,


\sf{=\frac{1}{2} m (v - u)^{2}}

\sf{= \frac {1}{2} \times 90 \times (50 - 30)^{2}}

\sf{= 45 × (20)^{2}}

\sf{= 45 × 400}

\sf{= 18000 \: J}




♥ •°• 18000 J of work would be required. ♥
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Thank you... (^_-)
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