How much work will be done in bringing a charge of 2*10^-3columbs from infinity to point p at which the potential is 5volt
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Given,
Q=2×10^-3 C
V= 5V
V=W/Q
W= V × Q
=5 × 2×10^-3
= 10 × 10^-3
=10^-2 J
=0.01J
Q=2×10^-3 C
V= 5V
V=W/Q
W= V × Q
=5 × 2×10^-3
= 10 × 10^-3
=10^-2 J
=0.01J
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