How much work will be done in bringing a charge of 3 x 10–2 coulombs from infinity to a point P at which the potential is 20 V?
Answers
Answered by
56
V=W/Q
W=VQ
W= 20×3×10^-2
W=6×10^-1
W=VQ
W= 20×3×10^-2
W=6×10^-1
Answered by
6
Answer:
Work done is 0.6 J
Explanation:
.Given
W is the work done in bring a charge
Q is the charge = 3x10^-2 C
V is the potential= 20 V
To find : Work will be done in bringing a charge of 3 x 10–2 coulombs from infinity to a point P at which the potential is 20 V.
Step by step explanation :
Potential difference = Work done / charge
Work done = potential difference x Charge
W=V.Q
W= 20x3x10^-2
W= 60x10^-2
W=0.6 joule
Work will be done in bringing a charge of 3 x 10–2 coulombs from infinity to a point P at which the potential is 20 V is 0.6 Joules.
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