Question

How much work will be done in bringing a charge of 5.0 milicolombs from infinity to a point P at which the potential is 12V?

Answer 1

Hi there !!

Charge = Q = 5mC = 0.005 C

Potential Difference = V = 12V

Work done = W

V = W/Q
 
12 = W / 0.005

W = 12 x 0.005
     = 0.06 Joules

work done = 0.06 joules

Answer 2

The Work done in bringing a charge from infinity to a point P is 0.06W.

Given:-

Charge (q) = 5*10-³C

Potential (v) = 12V

To Find:-

Work done in bringing a charge from infinity to a point P.

Solution:-

To find the work done, you should follow these simple steps.

Now,

Charge (q) = 5*10-³C

Potential (v) = 12V

Work (w) = ?

According to the formula,

$potential = \frac{wok \: done}{charge}$

$v = \frac{w}{q}$

$w = v \times q$

$w = 5 \times {10}^{ - 3} \times 12$

$w = 60 \times {10}^{ - 3}$

w = 0.06W

Hence, the Work done in bringing a charge from infinity to a point P is 0.06W.

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